Monday March 11, 2024 Day 40 Buffers: Qualitative Operation |
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Textbook Readings 17.1: The Danger of Antifreeze 17.2: Buffers: Solutions That Resist pH Change 14.6 Buffers |
Course Lectures 14.1 pdf Video Qualitative Buffer Operation |
Qualitative Buffer Operation |
Buffers |
Objectives 1. Identify the two key components of a buffer. 2. Describe how the weak acid and conjugate base levels affect the pH of a buffering system (i.e. more weak acid lowers the pH. More conjugate base increases pH) 3. Describe how the addition of a strong acid to a buffering solution changes the concentrations of weak acid and its conjugate base. 4. Describe how the addition of a strong base to a buffering solution changes the concentrations of weak acid and its conjugate base. |
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Homework Problems Answer these questions. Click and drag over the space below for answers. 32.1 Buffers are solutions that contain significant concentrations of a weak acid and its conjugate base. In the diagram below, vertical bar graphs are used to show the starting concentrations of a buffer's components: After the addition of a small amount of strong base the buffer maintains the H3O+ levels and the corresponding pH near their original levels. However, the buffer's weak acid and conjugate base components shift during the process: List all changes that take place after the strong base has been added. 32.2 If a strong acid is added to the buffer in 32.1, again the H3O+ levels and the corresponding pH's are near their original levels. However the buffer components have shifted. List all changes that take place after the strong base has been added. 32.3 NaHCO3 and K2CO3 solutions can be combined to form a buffer solution. However, HNO3 and KNO3 cannot be combined to form a buffer solution. Why? 32.4. Carefully adding NaOH to a weak acid solution will create a chemical buffer. Explain how this is possible. 32.5 Buffers have "capacity." Capacity is a measure of how much strong acid or base they can neutralize before one of the buffer's components is used up. Below are two buffers, both with equal concentrations of weak acid and conjugate base. Which has the greatest "capacity?" Explain your answer. 32. 6 Buffering systems can be "exhausted" when too much strong acid or strong base has been added and one of the buffer's components has been completely used up. Consider the following three buffers and decide which is better prepared to protect against pH changes if a strong acid is added. Click and drag the region below for correct answers 33.1 The addional strong base is neutralized by the buffer's weak acid component. Changes: weak acid levels decrease weak acid is converted into conjugate base conjugate base levels increase in a 1:1 manner The truth regarding [H3O+] and pH: The buffer does maintain [H3O+] and pH at relatively constant levels. That's what a buffer is supposed to do! However, the addition of a strong base to a buffer DOES produce a slight increase in pH and slightly lower H3O+ levels. Our bar graphs do not show this small change. 33.2 The addional strong acid is neutralized by the buffer's conjugate base component. Changes: weak acid levels increase conjugate base is converted into weak acid weak acid levels increase in a 1:1 manner The truth regarding [H3O+] and pH: The buffer does maintain [H3O+] and pH at relatively constant levels. That's what a buffer is supposed to do! However, the addition of a strong acid to a buffer DOES produce a slight decrease in pH and slightly higher H3O+ levels. Our bar graphs do not show this small change. 33.3 Mixing NaHCO3 and K2CO3 solutions releases the weak acid, HCO3- and it's conjugate base CO32- into the solution in significant amounts. That's all you need for a buffer. The K+ and Na+ ions are spectators and in no way affect the pH of the solution. However, HNO3 is a STRONG acid and aqueous KNO3 is a mixture of ions that cannot affect pH. Morale: you must have a weak acid and it's conjugate base to create a buffer. 33.4 Initially, a weak acid solution contains mostly the acid component in equilibrium with small amounts of H3O+ and the conjugate base. Adding NaOH carefully to the weak acid neutralizes the acid and CREATES the conjugate base as part of the process. Once conjugate base levels are significant, your solution is a buffer.... ....as long as you haven't completely neutralized the acid....you need that too! 33.5 "B" has the greater buffer "capacity" since there are greater levels (concentrations) of weak acid and conjugate base. Simply put, there is more acid/base to cope with strong acids or bases that may attempt to change the pH. 33.6 Additional strong acid will be neutralized by the buffer's conjugate base component. Thus, the buffer that has the greatest amount of conjugate base is best positioned for strong acid additions. This would be "A" Note that all three buffers have the same "capacity". Buffer "B" is best positioned to guard against strong acid OR strong base additions. It is actually at the 1/2 equivalence or pKa point on it's titration curves since concentrations of weak acid and conjugate base are equal. |
Tuesday March 12, 2024 Day 41 Buffers: Initial pH and the Henderson Hasselbalch Equation |
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Textbook Readings Henderson-Hasselbalch Approximation |
Course Lectures 14.2 pdf Video Buffer pH Calculations and the Henderson Hasselbalch equation 15.1 pdf Video Buffer: Initial pH |
Acid-Base Equilibria and Buffer
Solutions |
Practice Problem: Henderson-Hasselbalch
Equation Calculations |
Objectives 1. Given buffer component concentrations, calculate the pH of the buffer 2. Given initial concentrations and volumes of buffer components (pre-mixing), perform the dilution calculations and calculate the pH of the buffer using an ICE table. 3. Given initial concentrations and volumes of buffer components (pre-mixing), perform the dilution calculations and calculate the pH of the buffer using the Henderson Hasselbalch equation. 4. Explain what precautions must be observed when using the Henderson Hasselbalch equation (5% rule must apply) |
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Homework Problems 33.1 A buffer solution initially consists of 0.0500 NH3 and 0.0350 M NH4+. Ka for NH4 = 5.6 x 10-10 a. Perform an ICE ...AND... Henderson Hasselbalch pH calculation for the buffering system and verify the pH's are the same. b. Determine if the 5% rule is valid. (..a requirement for the H.H. equation). 33.2 A buffer solution initially consists of 0.250 CH3COOH and 0.450 M CH3COO-. Ka for CH3COOH = 1.76 x 10-5 What is the pH of the buffer (Your choice: H.H. equation or ICE) 33.3 A buffer is produced by mixing 250.0 mL of 0.150 M CH3COOH(aq) with 500.0 mL of 0f 0.250 M KCH3COO(aq). What is the initial pH of th buffer. (Be sure to perform the dilution calculations before calculating the pH) 33.4 In the lab, you have the following bulk solutions: .... 1 liter of 0.500 M CH3COOH ..... 1 liter of 0.750 M NaCH3COO Your job is to prepare 500.0 mL of a buffer whose pH = 4.90 What volume of each solution is required? Answers: Click and drag in the space below 33.1 pH = 9.41 Valid 33.2 pH = 5.012 33.3 pH = 5.277 33.4 Volume of acetic acid = 258.7 mL Volume of sodium acetate = 241.2 mL |
Wednesday March 13, 2024 Day 42 Bothering the buffer: Buffering Region pH's |
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Textbook Readings 14.6 Buffers |
Course Lectures 15.2 pdf Video Buffer: pH after 20 mL NaOH 15.3 pdf Video Buffer: pH at the half equivalence point |
Buffer: pH after 20 mL NaOH |
Buffer:
pH at the
half equivalence point |
Objectives 1. Correctly calculate the number of moles of NaOH or HCl added to a buffer. 2. Adjust the mole amounts of buffer's weak acid and conjugate base levels to reflect the addition of strong acid or base. 3. Calculate new solution concentrations using the new total volume (original buffer and added NaOH solution). 4. Solve ICE table for [H3O+] and pH 5. Decide whether answer is reasonable (pH increases for strong base addition, pH decreases for strong acid addition). |
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Homework Problems Answer these questions. Click and drag over the space below for answers. 34.1 A beaker 400.0 mL buffer solution has the following components present: weak acid [HA] = 0.650 M conjugate base [A-] = 0.350 M HA(aq) + H2O(l) ↔ H3O+(aq) + A-(aq) Ka = 4.55 x 10-6 What is the pH of the buffer both before and after the addition of 75.0 mL of 0.500 KOH? 34.2 A buffer is created by combining 325.0 mL of 0.750 M CH3COOH with 225.0 mL of 0.500 M NaCH3COO. What is the pH of the buffer both before and after the addition of 25.00 mL 1.00 M HCl? 34.3 What volume of 1.75 M NaOH would be required to position the buffer in 34.2 at it's ½ equivalence point (pKa point)? What is the pH of the buffer at this time? Answers: Click and drag in the space below 34.1 pH initial = 5.073 pHfinal = 5.244 Notice the pH went up as expected when adding a strong base. 34.2 pH initial = 4.419 pHfinal = 4.267 Notice the pH went down as expected when adding a strong acid. 34.3 pKa after addition of 37.5 mL of NaOH are required to reach the 1/2 equiv. point. pH = 4.754 |
Thursday March 14, 2024 Day 43 Bothering the Buffer: Equivalence Point pH's Beyond the Equivalence Point |
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Textbook Readings 14.6 Buffers |
Course Lectures 15.4 pdf Video Buffer: pH at the equivalence point 15.5 pdf Video Buffer: pH after excess base |
Buffer:
pH at the equivalence point |
Buffer: pH after excess base |
Objectives 1. Define what is meant by a buffer's acid and base equivalence point. 2. For strong acid or strong base addition, identify the buffer component that is depleted once the appropriate equivalence point has been reached. 3. Know how to determine the moles and volume of either strong base or strong acid required to reach the buffer's equivalence point. 4. Rewrite the weak acid or weak base equilibria as weak base or weak acid respectively 5. Calculate Ka from Kb or Kb from Ka 6. Determine [OH-], pOH and pH at either the acid or base equivalence point.. |
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Homework Problems 35.1 Consider the following 500.0 mL buffering system: CH3COOH(aq) + H2O(l) ↔ H3O+(aq) + NaCH3COO-(aq) Ka = 1.76 x 10-5 0.450M 0.350M a. What is the initial pH of the buffer? b. What volume of 0.750 M NaOH is required to reach the buffer's equivalence point? c. Use the weak base equilibrium to determine the pH at the equivalence point. 35.2 A buffer is created by adding 15.0 g of sodium butanoate (NaC4H7O2) to 675 mL of 0.800 M butanoic acid (HC4H7O2 Ka = 1.510 x 10-5) a. What is the initial pH of the buffer? b. How many mL of 2.00 M NaOH is required to reach the buffer's equivalence point? c. What is the pH of the buffer at it's equivalence point? d. Determine the excess OH- concentration of the solution if a total of 280.0 mL of 2.00 M NaOH has been added and use this to determine the pH of the solution. Answers: Click and drag in the space below 35.1 a. pHinitial = 4.645 = 4.648 (3 SF) b. 300.0 mL of NaOH required c. pH = 9.227 35.2 a. pHinitial = 4.223 b. 270. mL NaOH required to reach equivalence point c. pOH = 4.662 pH = 9.338 d. pH = 12.321 |